Mis vahe on monokromaatsete footonite lainepikkusel ja de Broglie footonite lainepikkusel?


Vastus 1:

ThedeBrogliewavelengthisgivenbyλ=h/p.ThePlanckEinsteinrelationis[math]E=hν.[/math]The de Broglie wavelength is given by \lambda=h/p. The Planck-Einstein relation is [math]E=h\nu.[/math]

Itfollowsthatforaphoton,νλ=(E/h)(h/p)=E/p=c,sothatthereisnodifferencebetweenthewavelengthandthedeBrogliewavelengthforphotonsinvacuum.It follows that for a photon, \nu \lambda = (E/h) (h/p) = E/p = c, so that there is no difference between the wavelength and the de Broglie wavelength for photons in vacuum.